Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 32

Answer

$a) -19$ $b) 3$ $c) 31$ $d) 102$

Work Step by Step

$a) f(-3)=6(-3)-1=-19$ $b)f(0)=7(0)+3=3$ $c) f(4)=7(4)+3=31$ $d) f(-100)+f(100) =[6(-100)-1]+[7(100)+3]$ $=[-600-1]+[700+3]$ $=[-601]+[703]$ $=102$
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