Answer
$a)-1$
$b)7$
$c)19$
$d)112$
Work Step by Step
$a)f(-2)=3(-2)+5=-1$
$b)f(0)=4(0)+7=7$
$c)f(3)=4(3)+7=19$
$d)f(-100)+f(100)=[3(-100)+5]+[4(100)+7]$
$=[-300+5]+[400+7]$
$=[-295]+[407]$
$=112$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 112: 31
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