Answer
$a.\displaystyle \quad \frac{1}{5}$
$b.\quad -4$
$c.\displaystyle \quad \frac{5}{4}$
$d.\displaystyle \quad \frac{29}{5}$
$e.\displaystyle \quad \frac{3a+3h-1}{a+h-5}$
Work Step by Step
$a.$
$f(0)=\displaystyle \frac{3(0)-1}{0-5}=\frac{-1}{-5}=\frac{1}{5}$
$b.$
$f(3)=\displaystyle \frac{3(3)-1}{3-5}=\frac{9-1}{3-5}=\frac{8}{-2}=-4$
$c.$
$f(-3)=\displaystyle \frac{3(-3)-1}{-3-5}=\frac{-9-1}{-3-5}=\frac{-10}{-8}=\frac{5}{4}$
$d.$
$f(10)=\displaystyle \frac{3(10)-1}{10-5}=\frac{30-1}{10-5}=\frac{29}{5}$
$e.$
$f(a+h)=\displaystyle \frac{3(a+h)-1}{a+h-5}=\frac{3a+3h-1}{a+h-5}$