Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 112: 17

Answer

$a.\quad 7$ $b.\quad -7$ $c.\quad 13$ $d.\quad 12$

Work Step by Step

$\left[\begin{array}{lll} x & f(x) & \\ x=0 & f(0)=(-0)^{3}-(0)^{2}-(0)+7 & \\ & =7 & \\ & & \\ x=2, & f(2)=(-2)^{3}-(2)^{2}-(2)+7 & \\ & =-8-4-2+7 & \\ & =-7 & \\ & & \\ x=-2 & f(-2)=(-(-2))^{3}-(-2)^{2}-(-2)+7 & \\ & =(2)^{3}-4+2+7 & \\ & =8-4+2+7 & \\ & =13 & \\ & & \\ x=1 & f(1)=(-1)^{3}-(1)^{2}-(1)+7 & \\ & =-1-1-1+7 & \\ & =4 & \\ x=-1 & f(-1)=(-(-1))^{3}-(-1)^{2}-(-1)+7 & \\ & =1^{3}-1+1+7 & \\ & =8 & \end{array}\right.$ $f(1)+f(-1)=4+8=12$
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