Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 112: 15

Answer

a.$f(0) = - 1$ b. $f(3) = 26$ c. $f(-4) = 19$ d.$f(b) = 2b^{2} + 3b - 1$ e. $f(5a) = 50a^{2} + 15a - 1$

Work Step by Step

$$f(x) = 2x^{2} + 3x - 1$$ a. f(0) $f(0) = 2(0)^{2} + 3(0) - 1$ $f(0) = - 1$ b. f(3) $f(3) = 2(3)^{2} + 3(3) - 1$ $f(3) = 2(9) + 9 - 1$ $f(3) = 18 + 9 - 1$ $f(3) = 26$ c. f(-4) $f(-4) = 2x^{2} + 3x - 1$ $f(-4) = 2(-4)^{2} + 3(-4) - 1$ $f(-4) = 2(16) + (-12) - 1$ $f(-4) = 32 -12 - 1$ $f(-4) = 19$ d. f(b) $f(b) = 2(b)^{2} + 3(b) - 1$ $f(b) = 2b^{2} + 3b - 1$ e. f(5a) $f(5a) = 2(5a)^{2} + 3(5a) - 1$ $f(5a) = 2(25a^{2}) + 15a - 1$ $f(5a) = 50a^{2} + 15a - 1$
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