Answer
a.$f(0) = - 1$
b. $f(3) = 26$
c. $f(-4) = 19$
d.$f(b) = 2b^{2} + 3b - 1$
e. $f(5a) = 50a^{2} + 15a - 1$
Work Step by Step
$$f(x) = 2x^{2} + 3x - 1$$
a. f(0)
$f(0) = 2(0)^{2} + 3(0) - 1$
$f(0) = - 1$
b. f(3)
$f(3) = 2(3)^{2} + 3(3) - 1$
$f(3) = 2(9) + 9 - 1$
$f(3) = 18 + 9 - 1$
$f(3) = 26$
c. f(-4)
$f(-4) = 2x^{2} + 3x - 1$
$f(-4) = 2(-4)^{2} + 3(-4) - 1$
$f(-4) = 2(16) + (-12) - 1$
$f(-4) = 32 -12 - 1$
$f(-4) = 19$
d. f(b)
$f(b) = 2(b)^{2} + 3(b) - 1$
$f(b) = 2b^{2} + 3b - 1$
e. f(5a)
$f(5a) = 2(5a)^{2} + 3(5a) - 1$
$f(5a) = 2(25a^{2}) + 15a - 1$
$f(5a) = 50a^{2} + 15a - 1$