Answer
a. $h(0) = 5$
b. $h(-1) = 8$
c. $h(4) = 53$
d. $h(-3) = 32$
e. $h(4b) = 48b^{2} + 5$
Work Step by Step
$$h(x) = 3x^{2} + 5$$
a. $h(0)$
$h(0) = 3(0)^{2} + 5$
$h(0) = 0 + 5$
$h(0) = 5$
b. $h(-1)$
$h(-1) = 3(-1)^{2} + 5$
$h(-1) = 3(1) + 5$
$h(-1) = 3+ 5$
$h(-1) = 8$
c. $h(4)$
$h(4) = 3(4)^{2} + 5$
$h(4) = 3(16) + 5$
$h(4) = 48 + 5$
$h(4) = 53$
d. $h(-3)$
$h(-3) = 3(-3)^{2} + 5$
$h(-3) = 3(9) + 5$
$h(-3) = 27 + 5$
$h(-3) = 32$
e. $h(4b)$
$h(4b) = 3(4b)^{2} + 5$
$h(4b) = 3(16b^{2}) + 5$
$h(4b) = 48b^{2} + 5$
