Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 12

Answer

$a) -3$ $b) -23$ $c) 0$ $d) 20b-3$ $e) 4b+17$

Work Step by Step

$a) g(0)=4\times0-3=-3$ $b) g(-5)=4\times(-5)-3=-23$ $c) g(\frac{3}{4})=4\times\frac{3}{4}-3=3-3=0$ $d) g(5b)=4\times5b-3=20b-3$ $e) g(b+5)=4(b+5)-3=4b+20-3=4b+17$
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