Answer
$a) -2$
$b) -17$
$c) 0$
$d) 12b-2$
$e) 3b+10$
Work Step by Step
$a) g(0)=3\times0-2=-2$
$b) g(-5)=3\times(-5)-2=-17$
$c) g(\frac{2}{3})=3\times\frac{2}{3}-2=2-2=0$
$d) g(4b)=3\times4b-2=12b-2$
$e) g(b+4)=3(b+4)-2=3b+12-2=3b+10$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 112: 11
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