Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 7

Answer

$a_1 = -4 \\a_2 = 5 \\a_3 = -6 \\a_4 = 7$

Work Step by Step

To find the first four terms of the given sequence, substitute 1, 2, 3, and 4 to $n$, respectively, then simplify. $a_1 = (-1)^1(1+3) = -1(4) = -4 \\a_2 = (-1)^2(2+3) = 1(5) = 5 \\a_3 = (-1)^3(3+3) = -1(6) = -6 \\a_4 = (-1)^4(4+3) = 1(7) = 7$
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