Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 54

Answer

$-2$

Work Step by Step

Since, we have from the graph: $\sum_{i=4}^{5}(\dfrac{a_i}{b_i})^3=(\dfrac{2}{-2})^3+(\dfrac{4}{-4})^3$ or, $=-1-1$ or, $=-2$
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