Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 829: 2

Answer

$a_1=3 \\a_2=7 \\a_3 = 11 \\a_4 = 15$

Work Step by Step

To find the first four terms of the given sequence, substitute 1, 2, 3, and 4 to $n$, respectively, then simplify. $a_1 = 4(1) - 1 = 4 - 1 = 3 \\a_2 = 4(2) - 1 = 8 - 1 = 7 \\a_3 = 4(3) - 1 = 12 - 1 = 11 \\a_4 = 4(4) - 1 = 16 - 1 = 15$
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