Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 89: 43

Answer

$2 \times 10^{-8}$

Work Step by Step

Divide the corresponding parts to obtain: $=\dfrac{4.8}{2.4} \times \dfrac{10^{-2}}{10^{6}} \\=2 \times 10^{-2-6} \\=2 \times 10^{-8}$
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