Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 82: 163

Answer

$$y=\frac{C-Ax}{B}$$

Work Step by Step

Solve $Ax + By = C$ for $y$. To solve for $y$, it must be isolated in one side. From the original equation, subtract $Ax$ on both sides: $$Ax-Ax + By = C-Ax$$ $$By = C-Ax$$ Divide both sides by B. $$\frac{By}{B} = \frac{(C-Ax)}{B}$$ $$y=\frac{C-Ax}{B}$$
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