Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 80: 75

Answer

$\dfrac{x^6}{25}$

Work Step by Step

RECALL: (i) The quotients-to-powers rule states that: $(\frac{a}{b})^n=\frac{a^n}{b^n}$ (ii) The power rule states that: $(a^m)^n=a^{mn}$ Use the quotients-to-powers rule to find: $=\dfrac{(x^3)^2}{5^2}$ Use the power rule to find: $=\dfrac{x^{3(2)}}{25} \\=\dfrac{x^6}{25}$
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