Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 107

Answer

$x^{16}$

Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}, a\ne0$ (ii) $(a^m)^n = a^{mn}$ Use rule (i) above to obtain: $=(x^{3-(-5)})^2 \\=(x^{3+5})^2 \\=(x^8)^2$ Use rule (ii) above to obtain: $=x^{8\cdot 2} \\=x^{16}$
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