Answer
$\dfrac{-12y^{15}}{x^3}$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}, a \ne0$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne0$
Divide the coefficients by each other and the variables by each other to obtain:
$=\dfrac{24}{-2} \cdot x^{2-5}y^{13-(-2)}
\\=-12 \cdot x^{-3}y^{13+2}
\\=-12x^{-3}y^{15}$
Use rule (ii) above to obtain:
$=-12 \cdot \dfrac{1}{x^3} \cdot y^{15}
\\=\dfrac{-12y^{15}}{x^3}$
