Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 62

Answer

$16x^{18}$

Work Step by Step

RECALL: (i) The products-to-powers rule states that: $(ab)^n=a^nb^n$ (ii) The power rule states that $(a^m)^n=a^{mn}$ Use the products-to-powers rule to find: $=(-4)^2(x^9)^2 \\=16(x^9)^2$ Use the power rule to find: $=16x^{9(2)} \\=16x^{18}$
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