Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 51: 66

Answer

x = 4/3

Work Step by Step

-2{7 - [4 - 2(1 - x) + 3]} = 10 - [4x - 2(x - 3)] Expand [4 - 2(1 - x) + 3]: 4 - 2 + 2x + 3 2 + 2x + 3 2x + 5 Expand 2(x - 3): 2x - 6 Rewrite the equation: -2[7 -(2x + 5)] = 10 - [4x - (2x - 6)] -2(7 -2x -5) = 10 - (4x - 2x + 6) -2(2-2x) = 10 - (2x + 6) -2(2-2x) = 10 - 2x - 6 -4+4x = -2x + 4 Add 4 to both sides: -4 + 4x + 4 = -2x + 4 + 4 4x = -2x + 8 Simplify 6x = 8 Divide both sides by 6: x = 8/6 or 4/3
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