Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 50: 45

Answer

conditional equation

Work Step by Step

Distribute $\frac{1}{2}$ then combine like terms to obtain: $\frac{1}{2}(6z) + \frac{1}{2}(20) -8 = 2z - 2(4) \\3z + 10 -8 = 2z - 8 \\3z + 2 = 2z - 8$ Subtract $2z$ and $2$ on both sides of the equation to obtain: $3z-2z=-8-2 \\z = -10$ The given equation has one solution so it is a conditional equation.
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