Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.2 - Operations with Real Numbers and Simplifying Algebraic Expressions - Exercise Set - Page 27: 58

Answer

$90$

Work Step by Step

$3\times(-2)$ is $-6$, so $-6(-1)(-5)(-3)$. $=6(-5)(-3)$ $=-30(-3)$ $=90$
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