Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.1 - Algebraic Expressions, Real Numbers, and Interval Notation - Exercise Set: 25

Answer

$46$

Work Step by Step

First, we must substitute x and y into the expression: $(8)^{2}-3(8-2)$ We now follow order of operations: First, we work inside the parenthesis $(8)^{2}-3(6)$ Then, we consider exponents $64-3(6)$ Then, we multiply outside of the parenthesis $64-18$ Finally, we subtract: $46$
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