Answer
$-12$
Work Step by Step
Multiply 12 (the LCD of the fractions) on both sides of the equation to obtain:
$\require{cancel}
12(\frac{x}{4}) = 12(2+\frac{x-3}{3})
\\\frac{12x}{4}= 24+ 12(\frac{x-3}{3})
\\3x= 24+ \cancel{12}4(\frac{x-3}{\cancel{3}})
\\3x=24+4(x-3)
\\3x=24+4x-12
\\3x=12+4x$
Subtract $3x$ on both sides of the equation to obtain:
$0=12+x$
Subtract $12$ on both sides of the equation to obtain:
$-12=x$
