Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.1 Parabolas and Circles - 9.1 Exercises - Page 702: 62

Answer

$x^2+y^2+8y=0$

Work Step by Step

Center=$(0,-4)$ Radius=$4$ Equation: $(x-0)^2+(y+4)^2=4^2$ $\implies x^2+y^2+8y+16=16$ $\implies x^2+y^2+8y=0$
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