Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 9 - Conic Sections, Sequences, and Series - 9.1 Parabolas and Circles - 9.1 Exercises - Page 702: 42

Answer

$x^2-8x+y^2-18y-14=0$

Work Step by Step

Center=$(7,1)$ Radius=8 Equation: $(x-7)^2+(y-1)^2=8^2$ $\implies x^2-14x+49+y^2-2y+1=64$ $\implies x^2-8x+y^2-18y-14=0$
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