Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Test: 32

Answer

$\frac{32}{41}-\frac{40i}{41}$

Work Step by Step

$\frac{8}{4+5i}$ =$\frac{8}{4+5i}\times\frac{4-5i}{4-5i}$ =$\frac{8(4-5i)}{4^{2}-(5i)^{2}}$ =$\frac{32-40i}{16-25i^{2}}$ =$\frac{32-40i}{16-25(-1)}$ =$\frac{32-40i}{41}$ =$\frac{32}{41}-\frac{40i}{41}$
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