Answer
$31-29i$
Work Step by Step
Step 1: $(7+2i)(3-5i)$
Step 2: $7(3-5i)+2i(3-5i)$
Step 3: $21-35i+6i-10i^{2}$
Step 4: As $i^{2}=-1$, we get $21-35i+6i-10(-1)$
Step 5: $21+10-35i+6i$
Step 6: $31-29i$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - Chapter Test - Page 672: 30
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