Answer
$6a\sqrt {5bc}$
Work Step by Step
$\sqrt {3ab}\times2\sqrt {15ac}$
=$2\times\sqrt {3ab}\times\sqrt {15ac}$
=$2\times\sqrt {3ab\times15ac}$
=$2\times\sqrt {9\times a^{2}\times5bc}$
=$2\times3a\sqrt {5bc}$
=$6a\sqrt {5bc}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - Chapter Test - Page 672: 20
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