Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 671: 89

Answer

$\frac{7}{5}-\frac{4}{5}i$

Work Step by Step

$\frac{4+7i}{5i}$ =$\frac{4+7i}{5i}\times\frac{5i}{5i}$ =$\frac{(4+7i)\times5i}{5i\times5i}$ =$\frac{20i+35i^{2}}{25i^{2}}$ =$\frac{20i+35(-1)}{25(-1)}$ =$\frac{20i-35}{-25}$ =$\frac{5(4i-7)}{-25}$ =$\frac{(4i-7)}{-5}$ =$\frac{(7-4i)}{5}$ =$\frac{7}{5}-\frac{4}{5}i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.