Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises: 89

Answer

$\frac{7}{5}-\frac{4}{5}i$

Work Step by Step

$\frac{4+7i}{5i}$ =$\frac{4+7i}{5i}\times\frac{5i}{5i}$ =$\frac{(4+7i)\times5i}{5i\times5i}$ =$\frac{20i+35i^{2}}{25i^{2}}$ =$\frac{20i+35(-1)}{25(-1)}$ =$\frac{20i-35}{-25}$ =$\frac{5(4i-7)}{-25}$ =$\frac{(4i-7)}{-5}$ =$\frac{(7-4i)}{5}$ =$\frac{7}{5}-\frac{4}{5}i$
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