Answer
$-16-30i$
Work Step by Step
$(3-5i)(3-5i)$
=$3(3-5i)-5i(3-5i)$
=$9-15i-15i+25i^{2}$
=$9-30i+25(-1)$
=$9-25-30i$
=$-16-30i$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 54
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