Answer
$29$
Work Step by Step
$(2+5i)(2-5i)$
=$2(2-5i)+5i(2-5i)$
=$4-10i+10i-25i^{2}$
=$4-10i+10i-25(-1)$
=$4-25(-1)$
=$4+25$
=$29$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 52
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