Answer
$7+22i$
Work Step by Step
$(5+4i)(3+2i)$
$=5(3+2i)+4i(3+2i)$
$=15+10i+12i+8i^{2}$
$=15+22i+8i^{2}$
$=15+22i+8(-1)$
$=7+22i$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 44
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