Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 78

Answer

$\frac{90+9\sqrt{3gh}+80\sqrt{2g}+8g\sqrt{6h}}{100-3gh}$.

Work Step by Step

The given expression is $=\frac{9+4\sqrt{8g}}{10-\sqrt{3gh}}$ $=\frac{9+4\sqrt{4\cdot 2g}}{10-\sqrt{3gh}}$ $=\frac{9+8\sqrt{ 2g}}{10-\sqrt{3gh}}$ Multiply and divide by the conjugate of the denominator. $=\frac{9+8\sqrt{2g}}{10-\sqrt{3gh}}\cdot \frac{10+\sqrt{3gh}}{10+\sqrt{3gh}}$ Use the FOIL method. $=\frac{90+9\sqrt{3gh}+80\sqrt{2g}+(8\sqrt{2g})\cdot (\sqrt{3gh})}{100+10\sqrt{3gh}-10\sqrt{3gh}+(-\sqrt{3gh})(\sqrt{3gh})}$ Simplify. $=\frac{90+9\sqrt{3gh}+80\sqrt{2g}+8g\sqrt{6h}}{100-3gh}$.
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