Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 65

Answer

$\frac{(2\sqrt 3+3\sqrt {2})}{3}$

Work Step by Step

Step 1: $\frac{2+\sqrt 6}{\sqrt 3}$ Step 2: Rationalize the denominator: $\frac{(2+\sqrt 6)\times\sqrt 3}{\sqrt 3\times\sqrt 3}$. Step 3: $\frac{(2\sqrt 3+\sqrt {6\times3})}{\sqrt 3\times\sqrt 3}$ Step 4: $\frac{(2\sqrt 3+\sqrt {9\times2})}{3}$ Step 5: $\frac{(2\sqrt 3+3\sqrt {2})}{3}$
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