Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.3 Multiplying and Dividing Radicals - 8.3 Exercises - Page 643: 36

Answer

$16-2x$

Work Step by Step

Step 1: $(4-\sqrt {2x})(4+\sqrt {2x})$ Step 2: $4(4+\sqrt {2x})-\sqrt {2x}(4+\sqrt {2x})$ Step 3: $16+4\sqrt {2x}-4\sqrt {2x}-(\sqrt {2x})^{2}$ Step 4: $16-2x$
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