Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.2 Simplifying, Adding, and Subtracting Radicals - 8.2 Exercises - Page 634: 53

Answer

$6\sqrt[3] a$

Work Step by Step

$\sqrt[3] {8a}+4\sqrt[3] a=(\sqrt[3] 8\times\sqrt[3] a)+4\sqrt[3] a=(2\times\sqrt[3] a)+4\sqrt[3] a=2\sqrt[3] a+4\sqrt[3] a=6\sqrt[3] a$
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