Answer
$= \frac{(x-11)(x+9)}{(x-4)^{2}} $
Work Step by Step
$\frac{x^{2}-16x+55}{x^{2}-x-12} \times \frac{x^{2}+12x+27}{x^{2}-9x+20}$
$= \frac{(x-5)(x-11)}{(x-4)(x+3)} \times \frac{(x+9)(x+3)}{(x-4)(x-5)}$
$= \frac{(x-5)(x-11)(x+9)(x+3)}{(x-4)(x+3)(x-4)(x-5)} $
$= \frac{(x-11)(x+9)(x+3)}{(x-4)(x+3)(x-4)} $
$= \frac{(x-11)(x+9)}{(x-4)(x-4)} $
$= \frac{(x-11)(x+9)}{(x-4)^{2}} $