Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises - Page 580: 13

Answer

$= \frac{(x+7)^{2}}{(x-3)(x-9)} $

Work Step by Step

$\frac{(x+3)(x+7)}{(x-2)(x+3)} \times \frac{(x+7)(x-2)}{(x-3)(x-9)}$ $= \frac{(x+7)}{(x-2)} \times \frac{(x+7)(x-2)}{(x-3)(x-9)}$ $= \frac{(x+7)(x+7)(x-2)}{(x-2)(x-3)(x-9)} $ $= \frac{(x+7)(x+7)}{(x-3)(x-9)} $ $= \frac{(x+7)^{2}}{(x-3)(x-9)} $
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