Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises - Page 580: 1

Answer

$= xy^{2}$

Work Step by Step

$\frac{15x^{2}}{9y^{3}} \times \frac{21y^{5}}{35x}$ $= \frac{15x^{2}}{9y^{3}} \times \frac{21y^{5}}{35x}$ $= \frac{15x^{2}(21y^{5})}{9y^{3}(35x)}$ $= \frac{315x^{2}y^{5}}{315y^{3}x}$ $= \frac{x^{2}y^{5}}{xy^{3}}$ $= \frac{xy^{5}}{y^{3}}$ $= \frac{xy^{2}}{1}$ $= xy^{2}$
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