Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.2 Simplifying Rational Expressions - 7.2 Exercises - Page 575: 30

Answer

$= \frac{5b}{4} - 1 - \frac{3}{2b}$

Work Step by Step

$\frac{5b^{3}-4b^{2}-6b}{4b^{2}}$ $= \frac{b(5b^{2}-4b-6)}{b(4b)}$ $= \frac{5b^{2}-4b-6}{4b}$ $= \frac{5b^{2}}{4b} - \frac{4b}{4b} - \frac{6}{4b}$ $= \frac{5b}{4} - 1 - \frac{3}{2b}$
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