Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.1 Rational Functions and Variation - 7.1 Exercises: 42

Answer

$\text{all real numbers}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ The domain of the given rational function, $ f(x)=\dfrac{x+8}{x^2+5x+21} ,$ are the values of $ x $ which will NOT make the denominator equal to $0.$ $\bf{\text{Solution Details:}}$ The denominator, $x^2+5x+21,$ is equivalent to $x(x+5)+21.$ The only time the expression $x(x+5)$ becomes a negative number is when $x$ is between $-5$ to $0$ (exclusive). But with $+21,$ the denominator still becomes positive. Any other value of $x$ guarantees that the denominator is a positive real number. Hence, the denominator is always a positive real number (i.e. the denominator never becomes $0.$) Hence, the domain is the set of $ \text{all real numbers} .$
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