Chapter 6 - Logarithmic Functions - Chapter Review Exercises - Page 541: 2

$g^{-1}(t) = -\frac{t-6}{2}$

$g(t) = -2t+6$ Let $g(t) = y$ $y = -2t + 6$ Swap the variables $t$ and $y$ and then solve for $y$ to find the inverse: $t = -2y + 6$ $t - 6 = -2y$ $y = -\frac{t-6}{2}$ $g^{-1}(t) = -\frac{t-6}{2}$