Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 528: 73

Answer

$x \approx 10.514$

Work Step by Step

$3(1.6)^{x} - 20 = 400$ $3(1.6)^{x} = 400 + 20$ $3(1.6)^{x} = 420$ $(1.6)^{x} = 140$ $x = \log_{1.6} (140)$ $x = \frac{\log 140}{\log 1.6}$ $x = 10.5140...$ $x \approx 10.514$
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