Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 526: 6

Answer

$x\approx-0.638$

Work Step by Step

Take the log of both sides, and then use the power property. $9^x=0.246$ $x\log9=\log0.246$ $x=\frac{\log0.246}{\log9}$ $x\approx-0.638$
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