Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 526: 21

Answer

$x = 7$

Work Step by Step

$2500(\frac{1}{5})^{x} = 0.032$ $(\frac{1}{5})^{x} = \frac{0.032}{2500}$ $x = \log_{\frac{1}{5}} (\frac{0.032}{2500})$ by GDC / calculator $x = 7$
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