Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.2 Logarithmic Functions - 6.2 Exercises - Page 504: 92

Answer

$h^{-1}(t) = 9^{t}$

Work Step by Step

$h(t) = \log_9 t$ Let $h(t) = y$ $y = \log_9 t$ Swap the $t$ and $y$ variable to find the inverse: $t = \log_9 y$ $y =9^{t}$ $h^{-1}(t) = 9^{t}$
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