Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.6 Solving Quadratic Equations by Using the Quadratic Formula - 4.6 Exercises - Page 373: 38

Answer

$ k= 4.5,k=2.5$

Work Step by Step

The given expression is $\Rightarrow 7(2k-7)^2-11=17$ Add $11$ to both sides. $\Rightarrow 7(2k-7)^2-11+11=17+11$ Simplify. $\Rightarrow 7(2k-7)^2=28$ Divide both sides by $7$. $\Rightarrow \frac{7(2k-7)^2}{7}=\frac{28}{7}$ Simplify. $\Rightarrow (2k-7)^2=4$ Use the square root property. $\Rightarrow 2k-7=\pm\sqrt{4}$ Simplify. $\Rightarrow 2k-7=\pm 2$ Separate into two equaitons. $\Rightarrow 2k-7= 2$ and $2k-7=-2$ Add $7$ to each side of both equations. $\Rightarrow 2k-7+7= 2+7$ and $2k-7+7=-2+7$ Simplify. $\Rightarrow 2k= 9$ and $2k=5$ Divide each side of both equations by $2$ $\Rightarrow \frac{2k}{2}= \frac{9}{2}$ and $\frac{2k}{2}=\frac{5}{2}$ Simplify. $\Rightarrow k= 4.5$ and $k=2.5$ Check both answers using the graph. The graph is shown below.
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