Answer
$(a)f(x)+g(x)=-2x+68$
$(b)g(x)-f(x)=-32x$
$(c)f(x)g(x)=-25x^2-68x+1156$
$(d)\frac{f(x)}{g(x)}=\frac{15x+34}{-17x+34}$
Work Step by Step
$f(x)=15x+34$
$g(x)=-17x+34$
$(a)f(x)+g(x)$
$=15x+34+(-17x+34)$
$=15x+34-17x+34$
$=15x-17x+34+34$
$=-2x+68$
$(b)g(x)-f(x)$
$=-17x+34-(15x+34)$
$=-17x+34-15x-34$
$=-17x-15x+34-34$
$=-32x$
$(c)f(x)g(x)$
$=(15x+34)(-17x+34)$
$=15x(-17x+34)+34(-17x+34)$
$=-255x^2+510x-578x+1156$
$=-255x^2-68x+1156$
$(d)\frac{f(x)}{g(x)}=\frac{15x+34}{-17x+34}$
