Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - Chapter Review Exercises - Page 286: 7

Answer

45

Work Step by Step

(3m$^{-1}$n$^3$p$^{-2}$)$^2$$\times$(5m$^2$n$^{-6}$p$^4$) =($\frac{3n^3}{mp^2}$)$^2$$\times$($\frac{5m^2p^4}{n^6}$) =($\frac{9n^6}{m^2p^4}$)$\times$($\frac{5m^2p^4}{n^6}$) =$\frac{45m^2n^6p^4}{m^2n^6p^4}$=45
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.