Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - Chapter Review Exercises - Page 286: 3

Answer

$\frac{15a^4c^5}{b^3}$

Work Step by Step

$\frac{225a^5b^3c}{15ab^6c^{-4}}$ $=\frac{15a^{(5-1)}c^{(1+4)}}{b^{(6-3)}}$ $=\frac{15a^4c^5}{b^3}$
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