Answer
$\frac{15a^4c^5}{b^3}$
Work Step by Step
$\frac{225a^5b^3c}{15ab^6c^{-4}}$
$=\frac{15a^{(5-1)}c^{(1+4)}}{b^{(6-3)}}$
$=\frac{15a^4c^5}{b^3}$
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