Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises: 5

Answer

$(2t-7)^2$

Work Step by Step

The first term is $2t$ squared, the last term is $7$ squared, and the middle term is twice the negative product of these two terms. Now we can factor the trinomial into a binomial squared. $4t^2-28t+49$ $=(2t-7)(2t-7)$ $=(2t-7)^2$
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